Simple HW help

[montecarlo01ss]

A river flows at 50 m^3/s and a waste stream has a flow of 3 m^3/s. The
concentration of chlorides in the upstream part of the river (before the waste
stream) is 10.0 mg/m^3, and the concentration of chlorides in the waste stream is 200 mg/m3.
a) What is the downstream chloride concentration (after the waste stream joins the upstream part of the river) ?

 

[aaandht]

Got a formula?

Oh yeah, I think your professor is mad at you.
I need Help with Chemistry Please? - Yahoo! Answers

:lol:

 

[ESVEETEE]

50 m^3/s (10 mg/m^3) + 3 m^3/s (200 mg/m^3)




500 mg/s + 600 mg/s

1100 mg/s that's how much flows in per second


and 50 m^3/s + 3 m^3/s is flowing in


so it's 1100 mg/s / 53 m^3/s

or 1100/53 mg/m^3 or 20.75 mg/m^3


Keep in mind it's finals week so my brain is slightly fried, so if I'm wrong, go fly a kite. lol

 

[aaandht]

Its actually terrifying I had that written out. Finals FTL.

 

[Sarge_13]

Got a formula?

Oh yeah, I think your professor is mad at you.
I need Help with Chemistry Please? - Yahoo! Answers

:lol:

Bwahahaha :lol:

 

[montecarlo01ss]

haha no i do not attend the university of michigan, im not that smart.. but thats funny though its the same problem

 

[Blk04L]

Bwahahaha :lol:

What did it say? It now says the answer has been deleted.

 

[montecarlo01ss]

What did it say? It now says the answer has been deleted.

it was a teacher from the university of michigan asking if the student was in his class and basically saying they were in violation of the code of conduct lol

 

[Common]

hahaha, I dont know man, too many coincidences here!

 

[ESVEETEE]

Common, you should track down the identity of this student and the teacher. Email the teacher this thread, and wait for the lulz.

 

[montecarlo01ss]

hahaha, I dont know man, too many coincidences here!

ya on the side i like to call myself lucy... big passion for i love lucy shows :rolling:

 

[txyaloo]

Common, you should track down the identity of this student and the teacher. Email the teacher this thread, and wait for the lulz.

None of the professors teaching Engineering 101 this semester are named Leo. I already looked ;-)

Most likely this is a stock problem that came from the textbook publisher. Those are very easy to google for answers.

 

[JBR87]

50 m^3/s (10 mg/m^3) + 3 m^3/s (200 mg/m^3)




500 mg/s + 600 mg/s

1100 mg/s that's how much flows in per second


and 50 m^3/s + 3 m^3/s is flowing in


so it's 1100 mg/s / 53 m^3/s

or 1100/53 mg/m^3 or 20.75 mg/m^3


Keep in mind it's finals week so my brain is slightly fried, so if I'm wrong, go fly a kite. lol

this is the right answer... I just did the problem... unit analysis for the win... get good at that and you can do half of all engineering type questions

 

[lobra97]

swim with your eyes open?