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correct, you did, but for the wrong reasons.
There is no less weight transfer on ice than there is on dry road. If you are decelerating from 50 mph to 25 mph at the rate of 5 mph per second, there will the exact same amount of weight transfer on ice/snow as there will be on asphalt because the rate of deceleration is the same. Weight transfer is only affected when traction is affected.
First off, not all 4wd systems split the acceleration forces 50/50. Nissan skylines, r33 and r34 (if i'm not mistaken) are primarily rwd until the center diff decides the rear tires are spinning too much and the front tires need to step in.
Audi's quattro system is constantly scanning the wheel speeds and deciding what amount of power can go to what axle, but will never send more than 30% of the power to the front tires. This means they will never experience a 50/50 torque split.
However, in both of these examples, braking force stays at a constant (besides computer intervention in high performance driving situations). If a skyline driver is accelerating and the center diff decides on a 40/60 torque split, and the driver decides to use all the braking power possible, the brakes will still be doing their normal 70/30 or 65/35 or whatever their braking force is set to. The front tires will not be doing 40% of the braking simply because the center diff wanted them to do 40% of the braking.
The reason for this, and the answer to your question in bold is because they are completely separate systems.
The situation is the same in older trucks with open diffs and solid locked transfer cases. If someone is travelling along in a 1975 3/4 ton chevrolet and needs to brake, all four tires may be forced to do the same speed, but it is still the front brakes are still doing 80% of the braking.
In an earlier post, you state this:
This is 100% correct, but the rear wheels are not locking up because of even braking power. They are locking up because of mechanical drag/lockup. If the rear brakes are completely disabled and 4wd is locked in, the front/rear braking bias is 100%/0%. You are implying that because the drive system is forcing the rear tires to stay at the same speed as the front tires, the brakes are sharing the work. In your scenario, how can the rear brakes be doing the same amount of work as the front brakes if they are not even operational?
If the normal amount of pressure for the front brakes is 600 lbs per square inch, and the normal pressure for the rear brakes is 400 lbs per square inch, then the total pressure is 1000 lbs per square inch. When the brakes are applied at full power, in 2wd or 4wd, the front brakes are still pushing at 600 lbs, and the rear brakes are still pushing at 400 lbs.
If you cut off all fluid going to the rear brakes and try it again, the front brakes are still pushing at 600 lbs, where as the rear brakes are now pushing at 0 lbs. However, it's not braking force that's keeping the rear tire speed in check with the front tire speed, it's the gears inside the transfer case, transmission, and differential doing the work.
Everyone here gets what you are getting at, but you are simply thinking of it all wrong. Brake bias is just that, the bias by which the brakes are working. Brake bias is decided by a proportioning valve, brake fluid, and your foot, not the power of the engine or where the center diff/transfer case sends that power. Total stopping power will be affected by all of this, but total stopping power is not brake bias.
You can test this concept by putting your vehicle in 4wd, finding a loose surface and locking up the e-brake...I believe you'll find that all 4 tires lock up if the rears lock up(not all e-brakes work that well...)
Im pretty sure that braking force does not transfer through the driveline from the front wheels to the rear. I dont have the physics to back up my position but im pretty confident in it
In 2wd, the brake bias is mainly affecting the front wheels, which means the rear axle isn't providing a lot of braking force.
In slick conditions, braking bias should be closer to 50/50, as there will be less weight transfer.
When its locked into 4wd, front braking power is getting shared by both front and rear axles. So YES, the front pads are providing the stopping force, but it is being spread to both axles as the transfer case is locked in. If acceleration is split 50/50, why wouldn't braking power?
So, getting to my main point that braking bias should be closer to 50/50 under slick conditions, having it in 4wd equilizes the braking to 50/50. Which means better stopping.
In most vehicles (at least the ones I'm familiar with), the e-brake is completely separate from the brake fluid system; it's cable driven, and isn't even connected to the front wheels.
4wd helps, but as others have said, once it's gone, hang the hell on.
Rwd you can usually wrangle it back in.
Your mudders comment makes me lol.
I love when people think their big wide tires are going to help them get through the snow (not implying you said this). It makes me LOL.
Skinny > wide on ice and snow.
-f_r
Your mudders comment makes me lol.
I love when people think their big wide tires are going to help them get through the snow (not implying you said this). It makes me LOL.
Skinny > wide on ice and snow.
-f_r
Not entirely true. If they are the proper tread type then wider=better.
Mud tires really dont have that much gripping surface on something smooth like packed snow or ice. Its all about biting edges, and those big flat lugs only have 1 biting edge, but a bunch of smaller blocks on an A/T tire is probably going to provide alot better traction in snow/ice.
motortrend said:Myth: Wide tires provide better traction under all weather conditions. In fact, putting oversize snow tires on a car delivers better snow traction.
Fact: The opposite is actually true. Wide tires tend to "float" on deep snow, and the tread lugs never have a chance to "dig" through to the road surface to gain traction. Narrow tires are a better option in deep snow. The tire acts similarly to a knife cutting through butter; the blade works best when using the narrow edge to push through the butter rather than the wide flat side of the blade.
With similar tread designs, thinner will always be better. Less width equals more pressure per square inch. More pressure means it will be harder to lose traction and easier to get around, while giving the edges you talk about more chance to cut, on ice and packed snow.
Tread design is important for clearing loose snow, but not as important on ice and packed snow.
Big wide tires DO help get through the snow..... deep snow. now on ice, they suck.....I love when people think their big wide tires are going to help them get through the snow (not implying you said this). It makes me LOL.
-f_r
That car must have a center diff.
Big wide tires DO help get through the snow..... deep snow. now on ice, they suck.....